two parallel sides of an isosceles trapezium are 31 cm and 15 CM. its non parallel sides are each equal to 70 cm find the area of the trapezium.
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Answer: let the trapezium be ABCD=AB=15cm BC=70cm CD=31cm DA=70cm
hight of the trapezium =√bc²-ec²=√70²-8²=√4900-64=√4836cm=69·5cm
area of the trapezium =1/2×sum of parallel sides×hight
=1/2×15+ 31×69·5=23×69·5=1598·5cm²
Step-by-step explanation:first of all we have to find ihe hight of the trapazium so i have find it from that method then i find the area if it that is very eazy .
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