two parallel sides of an isosceles trapezium are 6 cm and 14 cm respectively. if the length of each non - parallel side is 5 cm, find the area of the trapezium .
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Answer:
Step-by-step explanation:
we know the area of the trapezium=1/2*sum of parallel sides*height
given
it is isoceles
14-6=8cm
8/2=4cm
we have one non parallel side that is 5cm
so h sq=5sq - 4sq
h=3cm
so area=1/2*20*3
=30cmsq
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