two parallel sides of an isosceles trapezium are 6 cm and 14 cm respectively. if the length of each non parallel side is 5 cm, find the area of the trapezium.
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see, dividing the trapezium into two triangle and one rectangle,
rectangle having one side =6 cm
triangle's sides are 5cm and 4cm
To find the third side or the perpendicular distance between both parallel lines,
Apply pythagoras' theorem.
height =√((5)² -(4)²)
= 3 cm
so, area = (1/2)×(sum of parallel side)×(distance between them)
= (1/2)×(6+ 14)×3
= 30 cm²
rectangle having one side =6 cm
triangle's sides are 5cm and 4cm
To find the third side or the perpendicular distance between both parallel lines,
Apply pythagoras' theorem.
height =√((5)² -(4)²)
= 3 cm
so, area = (1/2)×(sum of parallel side)×(distance between them)
= (1/2)×(6+ 14)×3
= 30 cm²
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friend here is your answer.
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