Two parallel sides of an isosceles trapezium are 6 cm and 14 cm respectively if the length of a non parallel side is 5 cm find the area of the trapezium
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Answered by
172
we know the area of the trapezium=1/2*sum of parallel sides*height
given
it is isoceles
14-6=8cm
8/2=4cm
we have one non parallel side that is 5cm
so h sq=5sq - 4sq
h=3cm
so area=1/2*20*3
=30cmsq
given
it is isoceles
14-6=8cm
8/2=4cm
we have one non parallel side that is 5cm
so h sq=5sq - 4sq
h=3cm
so area=1/2*20*3
=30cmsq
Answered by
89
hope it helps !!!! :-) :-)
the answer is 30cm square
the answer is 30cm square
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