Question

two parallel sides of trapezium ABCD are of lengths 10cm and 19cm respectively and the distance between them is 12cm . find the area of the trapezium​

Answer 1

Answer:

174   $cm^{2}$

Step-by-step explanation:

Area of trapezium = $\frac{1}{2}$ × sum of parallel sides × height

                               =$\frac{1}{2}$ × ( 10 + 19 ) × 12

                               =$\frac{1}{2}$ × 29 × 12

                                = 714 $cm^{2}$