two parallel sides of trapezium are 25 and 13 non parallel sidess are equal and 10 find area
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The non-parallel sides of the trapezium are equal - it is an isosceles trapezium. WLG, let us consider the 25 cm side to be the base. The difference in the lengths of the parallel sides is 25−13=12 cm25−13=12 cm. This will be split equally on both sides as the ‘extra’ or extending part of the base.
Now, you’ve got right angled triangles on both the sides, with a hypotenuse of length 10 cm10 cmand a base of 122=6 cm122=6 cm.
From Pythagoras’ Theorem, we can determine the height of the triangle to be 8 cm8 cm. The lengths of the sides are a Pythgorean triplet.
So, the area, ΔΔ is:
Δ=12×8 cm×(25+13) cm
Now, you’ve got right angled triangles on both the sides, with a hypotenuse of length 10 cm10 cmand a base of 122=6 cm122=6 cm.
From Pythagoras’ Theorem, we can determine the height of the triangle to be 8 cm8 cm. The lengths of the sides are a Pythgorean triplet.
So, the area, ΔΔ is:
Δ=12×8 cm×(25+13) cm
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