Math, asked by sunilinsan098876, 1 year ago

two parallel sides of trapezium are 60 cm and 77 CM other side are 25 cm find area of trapezium please solve in notebooks and send me

Answers

Answered by Sree33

Draw a line BC parallel to AD
Draw a perpendicular line BE on DF
ABCD is a parallelogram.
BC=AD=25cm
CD=AB=60cm
CF=77-CD=17cm

For Δ BCF
perimeter of triangle=(25+26+17)/2
=68/2=34
By Heron's Formula of triangle=√s(s-a)(s-b)(s-c)
=√34(34-25)(34-26)(34-17)
=204cm²

Now area of ΔBCF=1/2xbase x height
=1/2 BExCF204cm²
=1/2x BEx17BE
=408/17
=24cm

Area of Trapezium =1/2(AB+DF)xBE
=1/2(60+77)x24
=1644cm²

sunilinsan098876: hai

Sree33: Yes

Sree33: Can u say in english

Sree33: Once more

sunilinsan098876: you have write 26 in perimeter of triangle but there was an Number that's 25

sunilinsan098876: that's why your question is wrong

sunilinsan098876: vese thanks

Sree33: Its correct only

Sree33: Pls mark me as brainlist

sunilinsan098876: I don't know that where is the brain list option

Answered by indusinghkancha

Answer_1370cm²-explained in the following picture.

#Mark as the Brainliest
Regard
Team Kancha

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