two parallel sides of trapezium are 60cm and 77cm and the other two sides are 25cm and 26 cm. find the area of trapezium
Answers
Answer:
Draw a line BC parallel to AD.
Draw a perpendicular line BE on DF
ABCD is a parallelogram.
BC=AD=25cm
CD=AB=60cm
CF=77-CD=77-60=17 cm
For Δ BCF
s =(25+26+17)/2 =68/2=34
By Heron's Formula of triangle=√s(s-a)(s-b)(s-c)
=√34(34-25)(34-26)(34-17)
= 204cm²
Now area of ΔBCF=1/2 x base x height
=1/2 BE x CF 204cm²
=1/2 BE x 17BE
=408/17 = 24cm
Area of Trapezium =1/2 (AB+DF) x BE
=1/2(60+77)x24
=1644cm²
Thus, the area of the trapezium is 1644 cm².
Hope it helps.
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Step-by-step explanation:
Given a trapezium whose parallel sides are 77 cm and 60 cm and the other sides are 25 cm and 26 cm.
we have to find the area of trapezium.
AD=60 cm
BD=77 cm
AB=25 cm
DC=26 cm
EC=BC-BE=77-60=17 cm
In triangle DEC
By Heron's formula,
Area of triangle DEC can be calculated as
Now, area of trapezium can be calculated as