Question

Two parallel sides of trapezium are 85cm and 63cm and it's area 2664cm square find its altitude

Answer 1

Length of paralell sides are 85 cm and 63 cm

Area of trapezium = 2664
=> (a+b) * Height /2 = 2664
=> (85+63) * Height = 2664 * 2
=> 148 *Height = 2664 * 2
=> Height = 18 * 2
=> Height = 36 cm

Answer 2

Given : Two parallel sides of trapezium as 85 cm and 63 cm and it's Area = 2664 cm² .

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To find : Altitude (Ket's say x).

$\begin{gathered} \\ \\ \qquad{ \rule{280pt}{2pt}} \\ \end{gathered}$

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SolutioN :-

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$\bf{\dag} \;$We know area of a trapezium ;

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$\bigstar \: \: \: \boxed{ \sf{ \: =\dfrac{1}{2} \times altitude \times sum \; of \; its \; parallel \; sides \: }}$

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$\bf{\maltese} \;$Putting values, we get

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$\qquad \qquad\begin{gathered} \\ \\ : \implies \: \sf 2664=\dfrac{1}{2} \times h \times(85+63) \\ \\ \end{gathered}$

$\qquad \qquad\begin{gathered} \\ : \implies \: \sf 2664=\dfrac{1}{2} \times h \times \bf 148 \\ \\ \end{gathered}$

$\qquad \qquad\begin{gathered} \\ : \implies \: \sf h = \dfrac{2664}{74}\\ \\ \end{gathered}$

$\qquad \qquad\begin{gathered} \\ : \implies \: { \underline{ \boxed{\color{blue}{\pmb{\frak{h = 36}}}}}} \: \bigstar\\ \\ \end{gathered}$

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$\therefore \;$ The altitude of trapezium = 36.

$\begin{gathered} \\ \\ \underline{ \rule{300pt}{7pt}} \\ \end{gathered}$

Additional Information :-

$\begin{gathered} \begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Square} = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Triangle} = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Parallelogram} = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Trapezium} = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered} \end{gathered} \end{gathered} \end{gathered}$