Two parallel slits 1 mm apart are placed 1 metre away from screen. What is the fringe separation due to interference effect, when a beam of wavelength 500 nanometer is incident on them?
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Solution :
Given d=1mm
=1×10−3m
D=m
λ=500nm
=5×10−7m
β=λDd
=5×10−7×110−3
=0.5mm
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