two parallelogram are on equal bases and between the same parralels. the ratio of their area is
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Step-by-step explanation:
Let area of first parallelogram be P
1
And area of second parallelogram be P
2
⇒ Area of parallelogram =b×h
⇒ P
1
=b
1
×h
1
⇒ P
2
=B
2
×h
2
⇒ b
1
=b
2
[ As per the question ]
⇒ h
1
=h
2
[ As the distance between 2 parallel lines is always equal ]
∴ P
1
=b×h ------ ( 1 )
∴ P
2
=b×h
By equating ( 1 ) and ( 2 ) we get,
⇒ P
1
=P
2
⇒ P
1
:P
2
=1:1
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