Question

Two parallelograms are on same base and between same parallels.
The ratio of their areas is 1:1 (True/False)
or
Amedian of a triangle divide it in to triangle of equal area (True/False)​

Answer 1

Both statement are true.

Step-by-step explanation:

1. Area of each parallelogram between same two parallel line and same base are equal.

  This can be understood by

  Let Perpendicular distance between two parallel line = H = altitude

  Size of common base = B = base

  We know that area of parallelogram = Base × Altitude

  Area of parallelogram = B × H = This is also area of each parallelogram

 Means first statement is true.

2. Let a triangle's altitude = H

   and side of triangle which is perpendicular to altitude = B

   Median divide side of triangle into two equal parts = $\mathbf{\frac{B}{2}}$

   After divide by median into two triangle, each triangle size of base = $\mathbf{\frac{B}{2}}$

   So

  Area of each triangle = $\mathbf{\frac{1}{2}\times Base\times Altitude}$

  Area of each triangle  $\mathbf{=\frac{1}{2}\times \frac{B}{2}\times H}$ =This is also area of each triangle

  Means second statement is true.