Question

Two parellel sides of trapezium are 85cm and 63cm and its area is 2664cm2. Find its altitude

Answer 1

Step-by-step explanation:

$\bold{Given : }$

• Two Parallel sides of trapezium are 85 cm and 63 cm.

• Area of trapezium = 2664 cm²

$\bold{To \: find \: out : }$

Find the Altitude ( height ) of given trapezium?

$\bold{Formula \: used : }$

$\boxed{ \sf{Area \: of \: trapezium = \frac{1}{2} \times (b1 + b2) \times h}}$

$\bold{Solution : }$

We have,

⋆ b1 = 85 cm and b2 = 63 cm

⋆ Area = 2664 cm²

We know that,

$\sf{Area \: of \: trapezium} = \frac{1}{2} \times (b1 + b2) \times h$

$: \implies2664 = \frac{1}{2} \times (85 + 63) \times h$

$: \implies2664 = \frac{1}{2} \times 148 \times h$

$: \implies2664 = 74 \times h$

$: \implies \: h = \cancel \frac{2664}{74}$

$: \implies \: h = 36 \: cm$

Hence, the height of given trapezium is 36 cm

Answer 2

Given:

Two parellel sides of trapezium are 85cm and 63cm and its area is 2664cm².

To find:

Find its Altitude?

Formula used:

Area of trapezium = 1/2 ( sum of parallel sides) × height

Solution :

Let the Altitude be h .

Now,

Area of trapezium = 1/2 ( sum of parallel sides) × height

2664 cm² = 1/2 ( 85 cm + 63 cm ) × h

2664 cm² = 1/2 × 148 cm × h

2664 cm² = 74 cm × h

h = 2664 cm²/74 cm

h = 36 cm