Question

two particle A and B released from large height at t= 0 and t =1 second respectively . distance between two particle at t=3 second is​

Answer 1

Explanation:

Let distance be h

distance travelled by A-

1. d(1) =ut+1/2at^2
2. =0+1/2×-10×9= -45m
3. distance travelled by B in 2s =distance covered in 3s as it releases one sec later than A
4. therefore,
5. d(2)=0+1/2×-10×4= -20m
6. -ve sings indicate downward movement but magnitude of distance is only +ve
7. Distance b/w A and B = 45-20=25m