Question

two particle A and B released from large height at t= 0 and t =1 second respectively . distance between two particle at t=3 second is

Answer 1

for particle A,t=3sec,g=9.8m/s² ,u=0
h=0×3+1/2×9.8×9
h=4.9×9
h=44.1m from releasing point.

for B,u=0,g=9.8m/s²,t=2sec
h=0×2+1/2×9.8×4
h=4.9×4=19.6m

therefore distance between both particle A and B at t=3sec is equal to 44.1-19.6=24.5m(ans)

Answer 2

Given,

A and B release at time t=0 and t=1 second

To Find,

Distance between two particle at t=3 seconds

Solution,

Here,for particle A,

t=3sec,g=9.8m/s² ,u=0

h=0×3+1/2×9.8×9

h=4.9×9

h=44.1m from releasing point.

Also, for B,

u=0,g=9.8m/s²,t=2sec

h=0×2+1/2×9.8×4

h=4.9×4=19.6m

Distance between both particle A and B at t=3sec is

44.1-19.6=24.5m

Hence, distance between two particle at t=3 seconds is 24.5m.