Two particle of mass 1kg and 3kg have position vector 2i^+3j^+4k^ and -2i^+3j^-4k^.the centre of mass has a position vector?
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Answer:
i²
Explanation:
m
1
=1 kg
r
1
=2
i
^
+3
j
^
+4
k
^
m
2
=3 kg
r
2
=−2
i
^
+3
j
^
−4
k
^
position vector of centre of mass will be
r
=
m
1
+m
2
m
1
r
1
+m
2
r
2
=
4
2
i
^
+3
j
^
+4
k
^
−6
i
^
+9
j
^
−12
k
^
⇒
r
=
4
−4
i
^
+12
j
^
−8
k
^
=−
i
^
+3
j
^
−2
k
^
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