Two particle of masses m and 4m have linear
momenta in the ratio of 2:1. What is the ratio of
their kinetic energies?
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let linear momentum of m is 2x
and linear momentum of 4m is x
m×v = 2x (1)
4m ×v' = x. (2)
(1) ÷ (2)
v/4v' = 2 =⟩ v/v' = 8
Kinetic energy = 1/2 × mv²
= (m/4m)×(v/v')²
= 1/4 × (8)²
= 64/4 = 18
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