Physics, asked by abhishek254618, 1 year ago

Two particle p and Q are launched simultaneously as shown in figure. Find the minimum distance between particle in meters.

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Answers

Answered by dhruvpipariya2006
0

Answer:

6 m is the answer

Explanation:

happy indepence day

Answered by Sanav1106
1

The minimum Distance between the two particles is 15m.

GIVEN: Two particle p and Q are launched simultaneously as shown in figure.
TO FIND: The minimum distance between particle in meters
SOLUTION:

As we are given in the question,

There are two particles P and Q.

Also,

The minimum distance that is to be found when Q moves with the velocity of 10m/s,

As we know,

v=u+at

Using the values given in the question.

10=0+2t

t=5sec.

Therefore,

Distance traveled by P in 5 seconds is 5×10 = 50m.

And distance traveled by Q in 5 seconds is = 0.5×2×52 = 25m.

So,

The minimum distance between the two particles P and Q will be 40+25−50

=15m
Therefore,

The minimum Distance between the two particles is 15m.

#SPJ2

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