Two particle p and Q are launched simultaneously as shown in figure. Find the minimum distance between particle in meters.
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Answer:
6 m is the answer
Explanation:
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The minimum Distance between the two particles is 15m.
GIVEN: Two particle p and Q are launched simultaneously as shown in figure.
TO FIND: The minimum distance between particle in meters
SOLUTION:
As we are given in the question,
There are two particles P and Q.
Also,
The minimum distance that is to be found when Q moves with the velocity of 10m/s,
As we know,
v=u+at
Using the values given in the question.
10=0+2t
t=5sec.
Therefore,
Distance traveled by P in 5 seconds is 5×10 = 50m.
And distance traveled by Q in 5 seconds is = 0.5×2×52 = 25m.
So,
The minimum distance between the two particles P and Q will be 40+25−50
=15m
Therefore,
The minimum Distance between the two particles is 15m.
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