Question

Two particles 1 and 2 are allowed to descend on two frictionless chords
OP and OQ. The ratio of the speeds of the particles 1 and 2 respectively
when they reach on the circumference is:​

Answer 1

Explanation:

Let radius of circle = R

Oq=Pq=R, So △OPq is a equilateral triangle

So Particle on chord OP will travel vertical distance = Rcos60=

2

R

∴ From work-energy theorem mg(R/2)=

2

1

mv

1

2

⟹v

1

=

Rg

Particle on chord OQ will travel vertical distance = 2R

Similarly for particle on OQ- v

2

=

4Rg

=2

Rg