Question

Two particles a and b are connected by a rigid rod ab the rod slides along perpendicular rail the velocity of a to the left is 10 m/s what is the velocity of b angle is60degre

Answer 1

I think 60° angle is from horizontal.

Final Answer : $\frac{10}{\sqrt{3}} m/s$

Steps:
1) We have,
$v_A = 10m/s$ leftward
Rod is Rigid.

Distance between any two points on road will be constant.

=> Velocity along the length of rod will be equal.
$=> v_B \cos(30\degree) = v_A \cos(60\degree) \\ => v_B \frac{\sqrt{3}}{2} = v_A \frac{1}{2} m/s \\ => v_B = \frac{10}{\sqrt{3}} m/s$

Hence, Velocity of point B is $\frac{10}{\sqrt{3}} m/s$ upward.

Answer 2

Answer:5.8m/s

Explanation:

Velocity of a (Va) =10m/s

Velocity of b (Vb)=?

a=60degree

tan 60degre =Va/Vb

Vb=Va/tan60

=10/under root 3

=5.8m/s