Question

Two particles A and B are in motion. If the wavelength associated with particle A is $5 \times 10^{-8}$ m, calculate the wavelength associated with particle B if its momentum is half of A.

Answer 1

From the given,

Two particles A and B are motion.

Wavelength of particle A = $5\times { 10 }^{ -8 }m$

Momentum associated with velocity of particle $A(mV{ ) }_{ A }\quad =\quad \frac { h }{ { \lambda  }_{ A } }$

Momentum associated with velocity of particle $B(mV{ ) }_{ B }\quad =\quad \frac { h }{ { \lambda  }_{ B } }$

                   $(mV{ ) }_{ B }\quad =\quad \frac { 1 }{ 2 } (mV{ ) }_{ A }$  

                   $\frac { h }{ { \lambda  }_{ B } } \quad =\quad \frac { h }{ { 2\lambda  }_{ A } }$

                   $=\quad 2\quad \times \quad 5\quad \times \quad { 10 }^{ -8 }m$

                   $=\quad 10\quad \times \quad { 10 }^{ -8 }\quad m$

                   ${ \lambda  }_{ B }\quad =\quad 1000\quad \AA$

Answer 2

Hey mate your answer will be.....

lamda{Wavelength}=1000°A


...answer....