Question

Two particles A and B are in motion. The momentum of particle B is the double of A . If momentum of particle B is the double of A. If the wavelength associated with the particle A is 5*10^-8m is calculate the wavelength associated with particle B

Answer 1

Answer:

Explanation:

Wavelength of the particle A = 5 x 10^-8 m

Let the momentum of particle A is pA and the momentum of the particle B is pB

Relation between pA and pB is :

pB = pA/2

pA = h/ 5 x 10^-8 m

pB = h/ 5 x 10^-8 m x 2

Wavelength of B(lambda) = h/pB

                    = h/ [h/ (5 x 10^-8 m) x 2]

                    = 10 x 10-8 m

                    = 10^-7 m

thnq