Question

Two particles A and B are initially at distance d apart. They start moving simultaneously at velocity v and u such that A always moves towards B and B moves along a fixed straight line which is perpendicular to initial direction of motion of A.Then they will meet after time

Answer 1

Considering particle A moves along x-axis with constant velocity of 6m/s, the displacement vector for A is 6t along x

Since B moves from rest after 8/3 sec A starts, the displacement vector for B is

1/2 *4*(t-8/3)^2 = 2*(t-8/3)^2

When you equate both and solve them you will get,

(t-8/3)^2 = 3t → t^2 - 25t/3 + 64/9 = 0 → t = 7.4 seconds