Question

Two particles A and B are moving with velocities 3 m/s and 4 m/s in mutually perpendicular direction. Magnitude of velocity of A with respect to B is​

Answer 1

Explanation:

Correct option is

C

rvasinθ−vbsinθ in anticlockwise direction

The angular speed on one particle with respect to other is given by the relative motion of first with respect to the second in direction perpendicular to the line joining them, divided by the distance between them.

Hence ω=rvay−vby

                =rvasinθ−vbsinθ in anticlockwise direction.