Two particles A and B are projected from the same point with the same speed but at different angles a and B with the horizontal, such that the maximum height of A is (2/3)rd of the horizontal range of B. Then which of the following relations are true
Answers
Answer:
sorry friend
Explanation:
i dont know the answer
Two particles A and B are projected from the same point with the same velocity of projection but at different angles α and β of projection, such that the maximum height of A is two-thirds of the horizontal range of B. then which of the following relations are true?
A. range of A= maximum height of B
B. 3(1-cos2α)=8sin2β
C. the maximum value of β is sin-1(3/4)
D. maximum horizontal range of A = u 2 / g and this occurs when β = (1/2)*sin − 1 ( 3/8 )
options B and D are correct.
Given:
Two particles A and B are projected with the same velocity
projection angle of A is α.
projection angle of B is β
Hmax of A = (2/3) x Range of B
To Find:
The relations which are true.
Solution:
From the given statement, Hmax of A = (2/3) x Range of B
we know, Hmax = u²sin²α/2g
Rb = u²sin2β/g
∴ u²sin²α/2g = 2u²sin2β/3g
sin²α = 4/3 x sin2β --------(2)
(1 - cos2α)/2 = 4/3 *2sinβcosβ
∴ 3(1-cos2α)=8sin2β --------(1)
Hence, relation b is correct.
From equation (1), βmax = 1/2*sin⁻¹(3/8).
Hence, relation c is incorrect.
Now substitute βmax in (2)
we get, α = 45° substitute in the range of A
Ra = u²sin2α/2g
= u²sin2(45°)/g
= u²sin90°/g
= u²/g (∵ sin 90° = 1)
Hence, relation D is correct.
Therefore, relations B and D are correct.
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