Two particles a and b are projected simultaneously from two towers of height 10 m and 20 m respectively particle is projected with an initial speed 10 root 2 metre per second at an angle of 45 degree while particle b is projected horizontally with 20 m/s if they collide
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no they will not collide as vertical component is not same for both projectiles
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Answered by
2
Answer:The height of particle Ag at any instant t is given as,
hA=10+uAs
i
n
45
0
t
−
1
2
g
t
2
h
A
=
10
+
10
√
2
s
i
n
45
0
t
−
1
2
g
t
2
=
10
+
10
t
−
1
2
g
t
2
Similarly, height of particle B at any instant
t
is given as,
h
B
=
20
−
1
2
g
t
2
At collision, both the heights are equal.
∴
10
+
10
t
−
1
2
g
t
2
=
20
−
1
2
g
t
2
⟹
t
=
1
s
Horizontal distance moved by particle A in 1 second is,
x
A
=
u
A
cos
45
o
×
t
=
10
√
2
c
o
s
45
0
×
1
=
10
m
Horizontal distance moved by particle B in 1 second is,
x
B
=
u
B
×
t
=
10
×
1
=
10
m
∴
d
=
x
A
+
x
B
=
10
m
+
10
m
=
20
m
Explanation:
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