Two particles A and B are projected with same speed so that the ratio of their maximum
heights reached is 3 : 1. If the speed of A is doubled without altering other parameters, the
ratio of the borzontal ranges attained by A and B is
Answers
Answered by
0
Explanation:
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H
1
=
4
2
25
sin
2
θ
1
4
2
25
sin
2
θ
1
=
1
3
sin
2
θ
2
sin
2
θ
1
=
1
3
.
sinθ
2
sinθ
1
=
3
sinθ
2
sinθ
1
=
2
1
2
3
Now v
1
=2u
R
2
R
1
=
4
2
g
sin20
2
(2u)
2
2
sin2θ
1
=
sin60
o
4×sin120
o
=4x
2
3
2
3
=4
R
2
R
1
=4:1
Answered by
1
Answer:
H2H1=4225sin2θ14225sin2θ1=13
sin2θ2sin2θ1=13.
sinθ2sinθ1=3
sinθ2
Explanation:
Two particles A and B are projected with same speeds so that ratio of their maximum heights reached is 3:1. If the speed of A is doubled without altering other parameters, the ratio of horizontal ranges attained by A and B is:
A
1:1
B
2:1
C
4:1
D
3:2
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ANSWER
H2H1=4225sin2θ14225sin2θ1=13
sin2θ2sin2θ1=13.
sinθ2sinθ1=3
sinθ2
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