Science, asked by Vempatibhargav23, 7 months ago

Two particles A and B are projected with same speed so that the ratio of their maximum
heights reached is 3 : 1. If the speed of A is doubled without altering other parameters, the
ratio of the borzontal ranges attained by A and B is​

Answers

Answered by narapogusudhakar777
0

Explanation:

please follow me

H

1

=

4

2

25

sin

2

θ

1

4

2

25

sin

2

θ

1

=

1

3

sin

2

θ

2

sin

2

θ

1

=

1

3

.

sinθ

2

sinθ

1

=

3

sinθ

2

sinθ

1

=

2

1

2

3

Now v

1

=2u

R

2

R

1

=

4

2

g

sin20

2

(2u)

2

2

sin2θ

1

=

sin60

o

4×sin120

o

=4x

2

3

2

3

=4

R

2

R

1

=4:1

Answered by rameensaif14062007
1

Answer:

H2H1=4225sin2θ14225sin2θ1=13

sin2θ2sin2θ1=13.

sinθ2sinθ1=3

sinθ2

Explanation:

Two particles A and B are projected with same speeds so that ratio of their maximum heights reached is 3:1. If the speed of A is doubled without altering other parameters, the ratio of horizontal ranges attained by A and B is:

A

1:1

B

2:1

C

4:1

D

3:2

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ANSWER

H2H1=4225sin2θ14225sin2θ1=13

sin2θ2sin2θ1=13.

sinθ2sinθ1=3

sinθ2

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