Question

Two particles A and B are released from same height at t= 0 and t= 2 seconds respectively. Distance between two particles at t = 4 second is (g* 10 ms?
16 m
40 m
60 m
80 m​

Answer 1

Answer:

60 m

Explanation:

S= ut + 1/2at^2

for 1st at t=4

S1= 0*4 + 1/2(10*16)=80

for 2nd at t = 4, it has travelled only for 2 sec

S2= 0*2 + 1/2(10*4)= 20

S1-S2= 60