Question

Two particles A and B are revolving on two
coplanar circles with time periods 4 second and 6
second respectively. Time period of particle A with
respect to B will be​

Answer 1

Answer:

The answer is 12s.

Explanation:

The time period of A with respect to B is 2π times. The reciprocal of the relative angular speed of A with respect to B.

Angular speed (ωAB) = 2π ( 1 /tA - 1/tB)

                                  = 2π ( 1/ 4s - 1/ 6s)

                                  = 2π/12s

Thus the time period of A with respect to B is  

        = 2π/ ωAB = 12s

After cancellatiuon it gives time period 12s.