Question

Two particles A and B enter a region of uniform magnetic field after being accelerated through the
same potential difference. They describe circular paths of radius 4 m and 2 m respectively. They
have the equal charge. Find the ratio of mass of A to the mass of B.
​

Answer 1

Answer:

$\dfrac{m_A}{m_B}=\dfrac{1}{2}$

Explanation:

Given that

Radius of A = 4 m

Radius of B = 2 m

Force F=  q .V .B

F= m a

So

ma = q.V.B

Given that charge (q) ,Velocity (V) and acceleration is same.

m ∝ B

We know that

B ∝ 1/r

So we can say that

m ∝ 1/r

$\dfrac{m_A}{m_B}=\dfrac{R_B}{R_A}$

$\dfrac{m_A}{m_B}=\dfrac{2}{4}$

$\dfrac{m_A}{m_B}=\dfrac{1}{2}$

Answer 2

Answer:

4:1 correct explanation