Question

Two particles a and b has charge +q and +4q, respectively, each having same mass m' allowed to fall from rest through same potential difference, then the ratio of speeds of a to that of b is

Answer 1

Answer:

we now that ∆U ( potential energy) = ∆V( potential) q(charge).

Explanation:

now we also know that ∆K.E =-∆U

SO K.E(q)/K.E (4q) => ∆U(q)/∆U(4q)

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