two particles a and b mass 150g and 250g respectively are approaching each other. Both particles have a speed of 3m/s . Find the magnitude of the total momentum of the system of the two particles
Answers
Answered by
0
Answer:
the answer is 1.20kg/m^2
Explanation:
Do give me brainliest answer
Answered by
0
Answer:
0.30 Ns
Explanation:
Mass of body A, ma = 150 g = 0.15 kg
Mass of body B, mb = 250 g = 0.25 kg
Both the bodies are moving towards each other. Let the direction of B be taken as positive. Then the direction of A will be considered negative.
Velocity of A, va = - 3 m/s
Velocity of B, vb = 3 m/s
Now, total momentum of the system,
P = mava + mbvb
=> P = (0.15)(-3) + (0.25)(3)
=> P = -0.45 + 0.75
=> P = 0.30 Ns
Similar questions