Question

two particles a and b move with constant velocities v1 and v2 along two mutually perpendicular straight lines towards the intersection point 0 .At moment the particle were located at distance L1 and L 2. from origin 0 respectively find the time when they are nearest and also the shortest distance

Answer 1

after time t 2 body move v1 t and v2 t. dist b/w them is p=root( ( L1-v1 t)^2) + ( L2-v2 t)^2). now solve dp/dt=0 to get t and then p.
if u hv doubt draw a diagram

Answer 2

Answer:

Answer :L1V2-L2V1/√V1^2+V2^2

I hope you have understood