Question

Two particles A and B of mass 10 g and 20 g respectively fall vertically. At a given time, the speed particle A is 12 m/s and that of B is 15 m/s. Find the total linear momentum of the system of the two particles​

Answer 1

Answer:

Mass of A = 10 g = $\sf{\frac{10}{1000}}$ = 0.01 kg

Velocity of A = 12 m/s

Mass of B = 20 g = $\sf{\frac{20}{1000}}$ = 0.02 kg

Velocity of B = 15 m/s

We know that :

$\boxed{\sf{Momentum=Mass \times Velocity}}$

Momentum of A = 0.01 × 12 = 0.12 kgm/s

Momentum of B = 0.02 × 15 = 0.3 kgm/s

Total Momentum = 0.12 kgm/s + 0.3 kgm/s

=》 0.42 kgm/s

Answer 2

Mass of A = 10 g =  = 0.01 kg

Velocity of A = 12 m/s

Mass of B = 20 g =  = 0.02 kg

Velocity of B = 15 m/s

We know that :

Momentum of A = 0.01 × 12 = 0.12 kgm/s

Momentum of B = 0.02 × 15 = 0.3 kgm/s

Total Momentum = 0.12 kgm/s + 0.3 kgm/s

=》 0.42 kgm/s