Two particles A and B of mass 10g and 20g respectively fall vertically. At a given time, the speed of particle A is 12m/s and that of B is 15m/s .Find the magnitude of the total linear momentum of the system of the two particles ?
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Answer:
p = mv
p1 = m1 × v1 p1 = 10 × 12 = 120 g.m/s
p2 = m1 × v1 p1 = 20 ×15 = 300 g.m/s
total linear momentum = (120 + 300 ) g.m/s = 420 g.m/s
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Mass of A = 10 g = = 0.01 kg
Velocity of A = 12 m/s
Mass of B = 20 g = = 0.02 kg
Velocity of B = 15 m/s
We know that :
Momentum of A = 0.01 × 12 = 0.12 kgm/s
Momentum of B = 0.02 × 15 = 0.3 kgm/s
Total Momentum = 0.12 kgm/s + 0.3 kgm/s
=》 0.42 kgm/s
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