Question

Two particles A and B of mass 10g and 20g respectively fall vertically. given time the speed of particle A is 12 m/s and that of B is 15 m/s find the total linear momentum of the system of the two particles.

Answer 1

Answer:

Explanation:

mass of particle A = 10 g= 0.010 kg

Velocity, v = 12 m/s

momentum = mv

= 0.010 kg X 12 m/s

= 0.12 kg m/s

mass of particle B = 20 g= 0.020 kg

Velocity, v = 15 m/s

momentum = mv

= 0.020 kg X 15 m/s

= 0.3 kg m/s

Total momentum = 0.12 kg m/s + 0.3 kg m/s

= 0.42 kg m/s downwards

Answer 2

Answer:

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Explanation:

P = mv

Mass of A = 10/1000 kg = 1/100 kg

Velocity of A = 12m/s

Momentum of A = 12/100 = 0.12 kg m/s

Mass of B = 20/1000 kg = 1/50 kg

Velocity of B = 15 m/s

Momentum of B = 15/50 = 30/100= 0.3 kg m/s

Total momentum = 0.3 + 0.12 = 0.42 downwards