Two particles A and B of masses 20 g and 30 g respectively are at rest at a certain time. Because
of the forces exerted by them on each other, the particles start moving. At a given instant, particle
A is found to move towards east with a velocity of 6 cm/sec. What is the velocity of particle B at
this instant (in cm/s)?
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Solution :-
- Mass of A = 20 g
- Mass of B = 30 g
Initially both the particles are at rest
Hence , the initial momentum of the system ( mass A + mass B ) is zero
➽ Pi = 0
Now ,
- Mass of A = 20 g
- Velocity of A = 6 cm /s
- Mass of B = 30 g
As no external force is acting on the system the total momentum of the system is conserved
By applying law of conservation of momentum ,
➽ Pi = Pf
➽ 0 = ma x v a + mb x v b
➽ - mb x vb = ma x va
➽ vb = - ma x va / mb
➽ vb = - 20 x 6 / 30
➽ vb = - 120 /30
➽ vb = -4 cm /s
The velocity of the particle is 4 cm /s towards the west
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