Question

Two particles A and B perform SHM along the same straight line with the same amplitude 'a', same
frequency of and same equilibrium position 'O'. The greatest distance between them is found to be
3a/2. At some instant of time they have the same displacement from mean position. What is the
displacement?
(A) a/2
(B) a 714 (C) 3a/2
(D) 3a/4
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Answer 1

The displacement is A√ 7 / 4

Explanation:

Let the chosen instant pp makes an angle \thetaθ with x-axis then.  

cosθ=  3  A/4 ÷ A  =   3/4

sinθ=  √ 7 / 4

The phase differences between two particles  

cos ( π/2 - θ)  = x / A

x = A cos ( π/2 - θ)

A sinθ = A√ 7 / 4

Displacement =  A√ 7 / 4

Hence the displacement is A√ 7 / 4.

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A particle is moving with 5 m/s and accelerated uniformly with 2 m/s2 for 10s find displacement in the last 1 sec. ?

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