Question

Two particles A and B start moving with velocities
20 m/s and 30/2 m/s along x-axis and at an angle
45° with x-axis respectively in xy-plane from origin.
The relative velocity of Bw.r.t. A​

Answer 1

Answer:

hay mate,,,,,

Explanation:

The relative velocity is 31.62 m/s

Explanation:

Given that,

Velocity of particle A v_{A} = 20\ m/sv

A

=20 m/s

Velocity of particle B v_{B} = 30\sqrt{2}\ m/sv

B

=30

2

m/s

Angle \theta=45^{0}θ=45

0

The component of particle A along x-axis

The component of particle A along y-axis

The component of particle B along x-axis

The component of particle B along y-axis

The velocity of AB along x-axis

The velocity of AB along y-axis

Now, the relative velocity of B w.r.t A

v_{AB}_{x}= \sqrt{v_{AB}_{x}^{2}+{v_{AB}_{y}^{2}+2\times v_{AB}_{x}\times v_{AB}_{y}\times cos\alpha}

Where,

v_{AB}_{x}= \sqrt{v_{AB}_{x}^{2}+{v_{AB}_{y}^{2}+2\times 0

Hence, The relative velocity is 31.62 m/s

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