Two particles A and B start moving with velocities
20 m/s and 30/2 m/s along x-axis and at an angle
45° with x-axis respectively in xy-plane from origin.
The relative velocity of Bw.r.t. A
Answers
Answer:
hay mate,,,,,
Explanation:
The relative velocity is 31.62 m/s
Explanation:
Given that,
Velocity of particle A v_{A} = 20\ m/sv
A
=20 m/s
Velocity of particle B v_{B} = 30\sqrt{2}\ m/sv
B
=30
2
m/s
Angle \theta=45^{0}θ=45
0
The component of particle A along x-axis
The component of particle A along y-axis
The component of particle B along x-axis
The component of particle B along y-axis
The velocity of AB along x-axis
The velocity of AB along y-axis
Now, the relative velocity of B w.r.t A
v_{AB}_{x}= \sqrt{v_{AB}_{x}^{2}+{v_{AB}_{y}^{2}+2\times v_{AB}_{x}\times v_{AB}_{y}\times cos\alpha}
Where,
v_{AB}_{x}= \sqrt{v_{AB}_{x}^{2}+{v_{AB}_{y}^{2}+2\times 0
Hence, The relative velocity is 31.62 m/s
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