Two particles A and B start their 1-D motion from origin at same instant. The acceleration of particle A is 1 m/s^2 and that of particle B is 0.5 m/s^2
Find relative distance between the two particles after 60s.
Please answer. I need it urgently.
Answers
Answer:
answr
search
What would you like to ask?
11th
Physics
Motion in a Plane
Relative Motion in 2 Dimension
Two particles A and B start...
PHYSICS
avatar
Asked on December 20, 2019 by
Sumon Adnaan
Two particles A and B start moving simultaneously along the line joining them in the same direction with acceleration of 1 m/s and 2 m/s and speeds 3 m/s and 1 m/s respectively. Initially A is 10 m behind B. What is the minimum distance between them?
HARD
Help best friend
Study later
ANSWER
Acceleration of A w.r.t B a
AB
=a
A
−A
B
=1−2=−1m/s
2
Initial velocity of A w.r.t B u
AB
=u
A
−u
B
=3−1=2m/s
∴ Distance traveled by A w.r.t B, S
AB
=u
AB
t+
2
1
a
AB
t
2
OR S
AB
=2t−
2
t
2
For maximum distance traveled
dt
dS
AB
=0
∴ 2−t=0 ⟹t=2 s
Thus maximum distance traveled S
AB
=2(2)−
2
2
2
=2 m
⟹ Minimum distance between the cars D
min
=10−2=8 m
solution
Answer ByavatarToppr
Answer:
answer is 15m/s and 900 m
Explanation:
hope you find the attachment
