Math, asked by sdey77433, 8 months ago

Two particles are executing SHM in parallel straight lines close to each other. Amplitude A and Time Period T of both the particles are equal. At time t=0, one particle is at displacement y1 = +A and other at y2 = -A/2, and they are approaching toward each other. After what time will they cross each other?​

Answers

Answered by vijaydk24
0
equation of motion of two particles executing S.H.M.  are y1​=10 sin⟮10πt+3π​⟯ m       y2​=10 cos⟮8πt+4π​⟯ m. The phase difference between these particles at t=0.5 s is

A .

127π​

B .

1213π​

C .

1225π​

D .

12π​

MEDIUM

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