two particles are in shm in parallel straight lines close to each other.amplitude a and time period t of both the particles are equal .at time t=0 ,one particle is at displacement y1=+a and other at y2=-a/2 ,and they are approaching toward each other .after what time they will cross each other
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V=wA where v:- velocity
w:-Omega
a:- amplitude
But w=2pi/T
Therefore,w1=2pi/T1 and w2=2pi/T2
Velocity is constant
A1=a and A2=-a/2
Therefore,
V1=w1A1
V2=w2A2
Since V1=V2
w1A1=w2A1
2pi/T1.a=2pi/T2.-a/2
a/T=-a/2T2
2T2=T1
w:-Omega
a:- amplitude
But w=2pi/T
Therefore,w1=2pi/T1 and w2=2pi/T2
Velocity is constant
A1=a and A2=-a/2
Therefore,
V1=w1A1
V2=w2A2
Since V1=V2
w1A1=w2A1
2pi/T1.a=2pi/T2.-a/2
a/T=-a/2T2
2T2=T1
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