Math, asked by vanialiasrani065, 9 months ago

Two particles are moving at a constant speed of 10m/s, one particle due North and the other
particle due South. The magnitude of relative velocity is 5n m/s, then the value of n is

Answers

Answered by abhi178
2

Two particles are moving at a constant speed of 10 m/s, one particle due North and the other particle due South. The magnitude of relative velocity is 5n m/s.

To find : The value of n is...

solution : 1st particle is moving at a constant speed of 10 m/s due north.

so velocity of the 1st particle, v₁ = 10j

2nd particle is moving at a constant speed of 10 m/s due south.

so velocity of the 2nd particle, v₂ = -10j

now relative velocity of 1st particle w.r.t 2nd , v₁₂ = v₁ - v₂

= 10j - (-10j)

= 20j

so the magnitude of relative velocity is 20m/s

but it has given that magnitude of relative velocity is 5n m/s.

so, 5n = 20 ⇒n = 4

Therefore the value of n = 4.

also read similar questions : a particle of mass 0.8g is moving at a constant speed 3 *10^2ms^-1.calculate change in momentum when a force of 5N acts ...

https://brainly.in/question/19192092

If n is a multiple of 5 and m=5n, which of the following will be the value of n + m?

https://brainly.in/question/5009096

Similar questions