two particles are moving in opposite directions each with a speed of 0.8c in laboratory frame of reference. find the velocity of one particle relative to other
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Given :
The speed of particle 1 (v₁) = 0.8c
The speed of particle 2 (v₂) = 0.8c
To find :
The velocity of one particle with respect to the other
Solution :
- The particles are moving in opposite direction, so one of the particles will have negative speed with respect to the other particle
- Relative velocity = v₂ - v₁
v₁₂ = v₂ - v₁
v₁₂ = 0.8c -(-0.8c)
v₁₂ = 0.8c + 0.8c
v₁₂ = 1.6c
The relative velocity of one particle with respect to the other is 1.6c.
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