Question

two particles are moving in same direction with speed 15m/s and 10m/s.initial distance between them is 100m.find the time after which they meet​

Answer 1

Answer:

Velocity of b with respect to a=30-5=25m/s

acceleration of b w.r.t.a=-10-0=-10m/s^2

s=20m=ut+1/2*a*t^2=25t-5t^2

t^2-5t+4=0

then t=4sec &t=1sec

distance travelled by b=x=ut+1/2*a*t^2

=30t-5t^2

at t=1 sec

x=30-5=25m

qt t=4sec

x=120-80=40m

so 40 m is answer.

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