Two particles are moving with velocities y and v2. Their relative velocity is the maximum, when the angle between their velocities is : (a) zero (b) 1/4 (c) t/2 (d) tt
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Explanation:Vrelative=v2-v1
Now
Since v2-v1 should be maximum
Hence sq root of v2square+v1square-2v1v2costheta=maxm
Min value of cos theta =-1 at 180
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