Physics, asked by mominmohsina7190, 1 year ago

Two particles are performing simple harmonic motion in a straight line about the same equilibrium point. the amplitude and time period for both particles are same and equal to a and t, respectively. at time t=0 one particle has displacement a while the other one has displacement 2 a − and they are moving towards each other. if they cross each other at time t, then t is :

Answers

Answered by Haashini
6
So, wt = π/3
The same constraint happens for x2, except that is moving in the other direction. So the closest value is wt+? = 2π/3.
To find out the phase difference ? between them, substitute π/3 for wt ion the equation wt+? = 2π/3,
wt+? = 2π/3
π/3+? = 2π/3
or, ? =2π/3 - π/3
= π/3
From the above observation we conclude that, the phase difference between the two particles will be π/3.
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