Question

Two particles are placed at some distance. If the mass of each of the two particles is doubled, keeping the distance between them unchanged, the value of gravitational force between them will be: *



(a) 1/4 times

(b) 4 times

(c) 1/2 times

(d) Unchanged

​

Answer 1

Answer:

C) 1/2 is the answer............

Answer 2

Answer

4 times

4 times Explanation: we know:

4 times Explanation: we know:F=G×

4 times Explanation: we know:F=G× r

4 times Explanation: we know:F=G× r 2

4 times Explanation: we know:F=G× r 2

4 times Explanation: we know:F=G× r 2 m

4 times Explanation: we know:F=G× r 2 m 1

4 times Explanation: we know:F=G× r 2 m 1

4 times Explanation: we know:F=G× r 2 m 1 ×m

4 times Explanation: we know:F=G× r 2 m 1 ×m 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G×

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2 F=4×G×

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2 F=4×G× r

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2 F=4×G× r 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2 F=4×G× r 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2 F=4×G× r 2 m

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2 F=4×G× r 2 m 1

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2 F=4×G× r 2 m 1

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2 F=4×G× r 2 m 1 ×m

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2 F=4×G× r 2 m 1 ×m 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2 F=4×G× r 2 m 1 ×m 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2 F=4×G× r 2 m 1 ×m 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2 F=4×G× r 2 m 1 ×m 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2 F=4×G× r 2 m 1 ×m 2

4 times Explanation: we know:F=G× r 2 m 1 ×m 2 F=G× r 2 2m 1 ×2m 2 F=4×G× r 2 m 1 ×m 2 The gravitational force between two objects varies directly as their masses and inversely as the square of the distance between them. So, when the masses of both objects are doubled without changing the distance, the gravitational force between them would become four times of the original value