two particles are projected from a tower horizontally in opposite directions with velocities 20 m/sand 10 m/s .find the time when their velocity vectors are mutually perpendicular . take g=10m/s^2
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Answer:√2s
Explanation:
V1= 20 i-10t j
V2= -10 I -10t j
Dot product of vectors is zero when they are perpendicular so solve to find t.
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