Two particles are projected from a tower horizontally in opposite directions with velocities 10m/s. & 20m/s. Find the time when their velocity vectors are mutually perpendicular. Take g=10m/s2 .
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Answer:
v1⋅v2 = 0
(u1+a1t)⋅(u2+a2t)=0
(10iˆ−10tjˆ)⋅(−20iˆ−10tjˆ)=0
−200+100t^2=0
t=√2 sec.
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