Physics, asked by harvim2005, 26 days ago

Two particles are projected from a tower horizontally in opposite directions with velocities 10m/s. & 20m/s. Find the time when their velocity vectors are mutually perpendicular. Take g=10m/s2 .​

Answers

Answered by ranirajan13481217
0

Answer:

v1⋅v2 = 0

(u1+a1t)⋅(u2+a2t)=0

(10iˆ−10tjˆ)⋅(−20iˆ−10tjˆ)=0

−200+100t^2=0

t=√2 sec.

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